If it's not what You are looking for type in the equation solver your own equation and let us solve it.
w^2+28w=52=0
We move all terms to the left:
w^2+28w-(52)=0
a = 1; b = 28; c = -52;
Δ = b2-4ac
Δ = 282-4·1·(-52)
Δ = 992
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{992}=\sqrt{16*62}=\sqrt{16}*\sqrt{62}=4\sqrt{62}$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(28)-4\sqrt{62}}{2*1}=\frac{-28-4\sqrt{62}}{2} $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(28)+4\sqrt{62}}{2*1}=\frac{-28+4\sqrt{62}}{2} $
| -1.2x=3(x+2.15) | | x/2+15=x+10 | | -5=p+11 | | 40112/x=92 | | 9=-3(n-1) | | f/8-22=27 | | 13/10(6)+15/10=i | | 4/13=m/13 | | -14+6n=6+5n+6n | | 8(s+4)=64 | | |5x^2-7x|=52 | | 23r=-138 | | 180+(9x-7)+90=360 | | 11x-11x=3 | | 9x-3+4x+2=90 | | -9t=81 | | -87=-(3r+8) | | 5x–3=2x–21 | | g(-7)=-21 | | 6x-10=160 | | 100x5−121x3=0 | | 0.15=y-45 | | .15=y-45 | | 6/5m+7=5 | | 30=12r | | (x+22)+(4x-37)=180 | | 1/2k+4=15 | | |4y−2|−3=−1 | | (x+22)=(4x-37) | | |4y−2|−3=−1. | | 2o+2=6o | | 7x=1057 |